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CQuestions

Are the following valid or not.

Nested loop. - New!

Print 1(true) or 0 (false) for following statements :

Program to calculate Simple interest using scanf() function.

Program to calculate simple interest in C

Program to calculate the Area of a Square.

Program to calculate the cube of number, Take a number from user.

Program to convert float into integer type.

Program to print adult for age 18, teenager for 13 to 18 and child for below 13.

What will be the output of this code

Write a program to calculate area of a circle.

Write a program to calculate perimeter of rectangle. Take sides, a and b from user.

Write a program to check if a number is divisible by 2 or not.

Write a program to check if a number is odd or even.

Write a program to check if a number is prime or not. - New!

Write a program to check if a student passed or failed.

Write a program to check if given character is digit or not.

Write a program to check whether a person is eligible for vote or not.

Write a program to find if a character entered by user is upper case or lower case.

Write a program to print the average of 3 numbers.

Write a program to print the grades to a student.

Write a program to print the table of number input by the user. - New!

program to (keep taking number as input from user until user enters a number which is multiple of 5.) - New!

write a program (keep taking numbers as input from user until user enters an Odd number) - New!

write a program to Print the sum of first n natural numbers.

write a program to calculate the sum of all numbers from 1 and 100. - New!

write a program to print all the odd numbers from 1 to 100. - New!

write a program to print reverse of the table for a number n. - New!

write a program to print the factorial of a number n. - New!

write a program to print the numbers from 0 to n, if n is given by user.

write a program to print the sum of first n natural numbers and also, print them in reverse.

LearnC

Conditional Statements.

Instructions and Operators in C.

Loop Control Statements - New!

Nested loop. - New!

c programming for beginners tutorial

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Write a program to check if a number is prime or not.

 //program to check if a number is prime or not. //number that is divisible only by itself and 1 (e.g. 2, 3, 5, 7) // 0 and 1 are not prime numbers. // 2 is the only even prime number. #include<stdio.h> int main() {     int n , a;          printf("enter any number\n");          scanf("%d", &n);          for(int i=1; i<=n; i++){ /*for loop is executed until the i value is equal to i*/ if(i%n==0){ a++; /* a will get increment if  i%n=0 */ } } if(a==2){ printf("n is a prime number"); }          else{         printf("n is not a prime number"); }          return 0; } output : enter any number 5 n is not a prime number -------------------------------- Process exited after 8.33 seconds with return value 0 Press any key to continue . .
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write a program (keep taking numbers as input from user until user enters an Odd number)

 //keep taking numbers as input from user until user enters an Odd number #include<stdio.h> int main() { int n; do{ printf("enter any number="); scanf("%d", &n); printf("%d\n", n); if(n % 2 !=0){ break; } } while(1); printf("you have entered an odd number "); return 0; } output : enter any number=0 0 enter any number=8 8 enter any number=6 6 enter any number=4 4 enter any number=2 2 enter any number=3 3 you have entered an odd number -------------------------------- Process exited after 11.81 seconds with return value 0 Press any key to continue . . .
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write a program to print all the odd numbers from 1 to 100.

//program to print all the odd numbers from 1 to 100. #include<stdio.h> int main() { for(int i=1; i<=100; i++){ if(i % 2 == 0){ // even number will be skiped continue; } printf("%d\n", i); } return 0; } output :  1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97 99 -------------------------------- Process exited after 0.0161 seconds with return value 0 Press any key to continue . . .
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